Base | Representation |
---|---|
bin | 1111010111001111111101… |
… | …1100101110111000101111 |
3 | 2012210212110021220111102012 |
4 | 3311303333130232320233 |
5 | 4203230003331130111 |
6 | 55532042225351435 |
7 | 3362261625346004 |
oct | 365637734567057 |
9 | 65725407814365 |
10 | 16892097130031 |
11 | 54229974aa072 |
12 | 1a8997519857b |
13 | 956bc18ab6a6 |
14 | 4258208c18ab |
15 | 1e46076e648b |
hex | f5cff72ee2f |
16892097130031 has 2 divisors, whose sum is σ = 16892097130032. Its totient is φ = 16892097130030.
The previous prime is 16892097129997. The next prime is 16892097130037. The reversal of 16892097130031 is 13003179029861.
It is a strong prime.
It is an emirp because it is prime and its reverse (13003179029861) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16892097130031 is a prime.
It is a super-2 number, since 2×168920971300312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16892097130037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8446048565015 + 8446048565016.
It is an arithmetic number, because the mean of its divisors is an integer number (8446048565016).
Almost surely, 216892097130031 is an apocalyptic number.
16892097130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
16892097130031 is an equidigital number, since it uses as much as digits as its factorization.
16892097130031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 489888, while the sum is 50.
The spelling of 16892097130031 in words is "sixteen trillion, eight hundred ninety-two billion, ninety-seven million, one hundred thirty thousand, thirty-one".
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