Base | Representation |
---|---|
bin | 11111011111000010… |
… | …10111110110001111 |
3 | 1121122000201221101221 |
4 | 33233201113312033 |
5 | 234104232424233 |
6 | 11433150344211 |
7 | 1135611366655 |
oct | 175741276617 |
9 | 47560657357 |
10 | 16903404943 |
11 | 7194593357 |
12 | 3338abb067 |
13 | 1794ca2679 |
14 | b64d36dd5 |
15 | 68de9642d |
hex | 3ef857d8f |
16903404943 has 2 divisors, whose sum is σ = 16903404944. Its totient is φ = 16903404942.
The previous prime is 16903404913. The next prime is 16903404961. The reversal of 16903404943 is 34940430961.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16903404943 - 233 = 8313470351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16903404943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16903404913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8451702471 + 8451702472.
It is an arithmetic number, because the mean of its divisors is an integer number (8451702472).
Almost surely, 216903404943 is an apocalyptic number.
16903404943 is a deficient number, since it is larger than the sum of its proper divisors (1).
16903404943 is an equidigital number, since it uses as much as digits as its factorization.
16903404943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 43.
The spelling of 16903404943 in words is "sixteen billion, nine hundred three million, four hundred four thousand, nine hundred forty-three".
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