Base | Representation |
---|---|
bin | 11000100111001010001… |
… | …000010101111110000011 |
3 | 12222200120112102101001012 |
4 | 120213022020111332003 |
5 | 210202302203111344 |
6 | 3332551214231135 |
7 | 233123215056116 |
oct | 30471210257603 |
9 | 5880515371035 |
10 | 1691313332099 |
11 | 5a2311313406 |
12 | 2339554b54ab |
13 | c364ab706b1 |
14 | 5bc07bba57d |
15 | 2dedcdd629e |
hex | 189ca215f83 |
1691313332099 has 2 divisors, whose sum is σ = 1691313332100. Its totient is φ = 1691313332098.
The previous prime is 1691313332083. The next prime is 1691313332101. The reversal of 1691313332099 is 9902333131961.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1691313332099 - 24 = 1691313332083 is a prime.
Together with 1691313332101, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1691313332029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 845656666049 + 845656666050.
It is an arithmetic number, because the mean of its divisors is an integer number (845656666050).
Almost surely, 21691313332099 is an apocalyptic number.
1691313332099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1691313332099 is an equidigital number, since it uses as much as digits as its factorization.
1691313332099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 708588, while the sum is 50.
The spelling of 1691313332099 in words is "one trillion, six hundred ninety-one billion, three hundred thirteen million, three hundred thirty-two thousand, ninety-nine".
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