Base | Representation |
---|---|
bin | 11111100010000101… |
… | …11100000000000001 |
3 | 1121200210212100011001 |
4 | 33301002330000001 |
5 | 234132304342433 |
6 | 11435502452001 |
7 | 1136341651501 |
oct | 176102740001 |
9 | 47623770131 |
10 | 16928980993 |
11 | 71a7a71a91 |
12 | 3345594001 |
13 | 179a388b22 |
14 | b684b3a01 |
15 | 69134957d |
hex | 3f10bc001 |
16928980993 has 2 divisors, whose sum is σ = 16928980994. Its totient is φ = 16928980992.
The previous prime is 16928980967. The next prime is 16928980997. The reversal of 16928980993 is 39908982961.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16852453489 + 76527504 = 129817^2 + 8748^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16928980993 is a prime.
It is a super-2 number, since 2×169289809932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16928980997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8464490496 + 8464490497.
It is an arithmetic number, because the mean of its divisors is an integer number (8464490497).
Almost surely, 216928980993 is an apocalyptic number.
It is an amenable number.
16928980993 is a deficient number, since it is larger than the sum of its proper divisors (1).
16928980993 is an equidigital number, since it uses as much as digits as its factorization.
16928980993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15116544, while the sum is 64.
The spelling of 16928980993 in words is "sixteen billion, nine hundred twenty-eight million, nine hundred eighty thousand, nine hundred ninety-three".
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