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169906998612809 is a prime number
BaseRepresentation
bin100110101000011110001110…
…010011000001001101001001
3211021120221122212102022202102
4212220132032103001031021
5134232224013121102214
61401210110403443145
750534242550100623
oct4650361623011511
9737527585368672
10169906998612809
114a157176283627
12170811460864b5
1373a621327b913
142dd5784cd1c13
151499a0e6bdbde
hex9a878e4c1349

169906998612809 has 2 divisors, whose sum is σ = 169906998612810. Its totient is φ = 169906998612808.

The previous prime is 169906998612803. The next prime is 169906998612811. The reversal of 169906998612809 is 908216899609961.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144797228381584 + 25109770231225 = 12033172^2 + 5010965^2 .

It is a cyclic number.

It is not a de Polignac number, because 169906998612809 - 212 = 169906998608713 is a prime.

It is a super-2 number, since 2×1699069986128092 (a number of 29 digits) contains 22 as substring.

Together with 169906998612811, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (169906998612803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84953499306404 + 84953499306405.

It is an arithmetic number, because the mean of its divisors is an integer number (84953499306405).

Almost surely, 2169906998612809 is an apocalyptic number.

It is an amenable number.

169906998612809 is a deficient number, since it is larger than the sum of its proper divisors (1).

169906998612809 is an equidigital number, since it uses as much as digits as its factorization.

169906998612809 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1632586752, while the sum is 83.

The spelling of 169906998612809 in words is "one hundred sixty-nine trillion, nine hundred six billion, nine hundred ninety-eight million, six hundred twelve thousand, eight hundred nine".