Base | Representation |
---|---|
bin | 110010101010011… |
… | …1111000101110101 |
3 | 11101110211221202022 |
4 | 1211110333011311 |
5 | 11440200000432 |
6 | 440404522525 |
7 | 60061522364 |
oct | 14524770565 |
9 | 4343757668 |
10 | 1700000117 |
11 | 7a2673282 |
12 | 3b53b0445 |
13 | 21127963a |
14 | 121ac57db |
15 | 9e3a3b12 |
hex | 6553f175 |
1700000117 has 2 divisors, whose sum is σ = 1700000118. Its totient is φ = 1700000116.
The previous prime is 1700000111. The next prime is 1700000147. The reversal of 1700000117 is 7110000071.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1432546801 + 267453316 = 37849^2 + 16354^2 .
It is a cyclic number.
It is not a de Polignac number, because 1700000117 - 24 = 1700000101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1700000095 and 1700000104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1700000111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 850000058 + 850000059.
It is an arithmetic number, because the mean of its divisors is an integer number (850000059).
Almost surely, 21700000117 is an apocalyptic number.
It is an amenable number.
1700000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1700000117 is an equidigital number, since it uses as much as digits as its factorization.
1700000117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 49, while the sum is 17.
The square root of 1700000117 is about 41231.0576750100. The cubic root of 1700000117 is about 1193.4832193072.
Adding to 1700000117 its reverse (7110000071), we get a palindrome (8810000188).
The spelling of 1700000117 in words is "one billion, seven hundred million, one hundred seventeen", and thus it is an aban number.
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