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17001623556013 is a prime number
BaseRepresentation
bin1111011101100111111110…
…1110111000111110101101
32020012100011101012102100211
43313121333232320332231
54212023311112243023
6100054234341022421
73403220036534125
oct367317756707655
966170141172324
1017001623556013
1154653912a1a98
121aa70413b4a11
13964327c46785
1442ac50c2bc85
151e73b7e45a0d
hexf767fbb8fad

17001623556013 has 2 divisors, whose sum is σ = 17001623556014. Its totient is φ = 17001623556012.

The previous prime is 17001623555993. The next prime is 17001623556023. The reversal of 17001623556013 is 31065532610071.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10771143291364 + 6230480264649 = 3281942^2 + 2496093^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17001623556013 is a prime.

It is a super-2 number, since 2×170016235560132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17001623556023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8500811778006 + 8500811778007.

It is an arithmetic number, because the mean of its divisors is an integer number (8500811778007).

Almost surely, 217001623556013 is an apocalyptic number.

It is an amenable number.

17001623556013 is a deficient number, since it is larger than the sum of its proper divisors (1).

17001623556013 is an equidigital number, since it uses as much as digits as its factorization.

17001623556013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 113400, while the sum is 40.

The spelling of 17001623556013 in words is "seventeen trillion, one billion, six hundred twenty-three million, five hundred fifty-six thousand, thirteen".