Base | Representation |
---|---|
bin | 100110101010011001010010… |
… | …010100100111010000011111 |
3 | 211022001120201202221121012011 |
4 | 212222121102110213100133 |
5 | 134241410122403242111 |
6 | 1401350522330452051 |
7 | 50546631212445265 |
oct | 4652312224472037 |
9 | 738046652847164 |
10 | 170039136384031 |
11 | 4a1a8213639932 |
12 | 170a2882894027 |
13 | 73b5811007525 |
14 | 2ddbd1c27a435 |
15 | 149d19505b021 |
hex | 9aa65252741f |
170039136384031 has 2 divisors, whose sum is σ = 170039136384032. Its totient is φ = 170039136384030.
The previous prime is 170039136383981. The next prime is 170039136384049. The reversal of 170039136384031 is 130483631930071.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 170039136384031 - 223 = 170039127995423 is a prime.
It is a super-2 number, since 2×1700391363840312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (170039136384431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85019568192015 + 85019568192016.
It is an arithmetic number, because the mean of its divisors is an integer number (85019568192016).
Almost surely, 2170039136384031 is an apocalyptic number.
170039136384031 is a deficient number, since it is larger than the sum of its proper divisors (1).
170039136384031 is an equidigital number, since it uses as much as digits as its factorization.
170039136384031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 979776, while the sum is 49.
The spelling of 170039136384031 in words is "one hundred seventy trillion, thirty-nine billion, one hundred thirty-six million, three hundred eighty-four thousand, thirty-one".
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