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17004200480117 is a prime number
BaseRepresentation
bin1111011101110001100101…
…0101000100110101110101
32020012120210222010201200022
43313130121111010311311
54212044100310330432
6100055342153254525
73403340640165314
oct367343125046565
966176728121608
1017004200480117
115466493966234
121aa7640404445
13964648a9a236
1442b01718427b
151e74b92b8b12
hexf7719544d75

17004200480117 has 2 divisors, whose sum is σ = 17004200480118. Its totient is φ = 17004200480116.

The previous prime is 17004200480089. The next prime is 17004200480131. The reversal of 17004200480117 is 71108400240071.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12293256118276 + 4710944361841 = 3506174^2 + 2170471^2 .

It is a cyclic number.

It is not a de Polignac number, because 17004200480117 - 216 = 17004200414581 is a prime.

It is a super-2 number, since 2×170042004801172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17004200480177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8502100240058 + 8502100240059.

It is an arithmetic number, because the mean of its divisors is an integer number (8502100240059).

Almost surely, 217004200480117 is an apocalyptic number.

It is an amenable number.

17004200480117 is a deficient number, since it is larger than the sum of its proper divisors (1).

17004200480117 is an equidigital number, since it uses as much as digits as its factorization.

17004200480117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12544, while the sum is 35.

The spelling of 17004200480117 in words is "seventeen trillion, four billion, two hundred million, four hundred eighty thousand, one hundred seventeen".