Base | Representation |
---|---|
bin | 11000101111101000111… |
… | …100001000111010111101 |
3 | 20000120002012112020001101 |
4 | 120233220330020322331 |
5 | 210324430030124323 |
6 | 3341055013213101 |
7 | 233564665614244 |
oct | 30575074107275 |
9 | 6016065466041 |
10 | 1700420161213 |
11 | 5a616493a964 |
12 | 235677331191 |
13 | c446c7b5987 |
14 | 5c42d47d95b |
15 | 2e372665dad |
hex | 18be8f08ebd |
1700420161213 has 2 divisors, whose sum is σ = 1700420161214. Its totient is φ = 1700420161212.
The previous prime is 1700420161207. The next prime is 1700420161267. The reversal of 1700420161213 is 3121610240071.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 947513400409 + 752906760804 = 973403^2 + 867702^2 .
It is a cyclic number.
It is not a de Polignac number, because 1700420161213 - 29 = 1700420160701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1700420161283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 850210080606 + 850210080607.
It is an arithmetic number, because the mean of its divisors is an integer number (850210080607).
Almost surely, 21700420161213 is an apocalyptic number.
It is an amenable number.
1700420161213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1700420161213 is an equidigital number, since it uses as much as digits as its factorization.
1700420161213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
The spelling of 1700420161213 in words is "one trillion, seven hundred billion, four hundred twenty million, one hundred sixty-one thousand, two hundred thirteen".
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