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170456421414613 is a prime number
BaseRepresentation
bin100110110000011101111010…
…011100101011011011010101
3211100112110211002100111112211
4212300131322130223123111
5134320224222340231423
61402310333213113421
750622033011622415
oct4660357234533325
9740473732314484
10170456421414613
114a34918710a574
121714b71a788871
137415c826c52c9
1430141c5d16645
1514a8e6918010d
hex9b077a72b6d5

170456421414613 has 2 divisors, whose sum is σ = 170456421414614. Its totient is φ = 170456421414612.

The previous prime is 170456421414569. The next prime is 170456421414641. The reversal of 170456421414613 is 316414124654071.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143646984619524 + 26809436795089 = 11985282^2 + 5177783^2 .

It is a cyclic number.

It is not a de Polignac number, because 170456421414613 - 213 = 170456421406421 is a prime.

It is a super-3 number, since 3×1704564214146133 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (170456421714613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85228210707306 + 85228210707307.

It is an arithmetic number, because the mean of its divisors is an integer number (85228210707307).

Almost surely, 2170456421414613 is an apocalyptic number.

It is an amenable number.

170456421414613 is a deficient number, since it is larger than the sum of its proper divisors (1).

170456421414613 is an equidigital number, since it uses as much as digits as its factorization.

170456421414613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1935360, while the sum is 49.

The spelling of 170456421414613 in words is "one hundred seventy trillion, four hundred fifty-six billion, four hundred twenty-one million, four hundred fourteen thousand, six hundred thirteen".