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1705640000153 is a prime number
BaseRepresentation
bin11000110100100000000…
…100001111101010011001
320001001112222120111221112
4120310200010033222121
5210421122320001103
63343321000350105
7234141230534465
oct30644004175231
96031488514845
101705640000153
115a83a3350141
12236693475335
13c4ac205687b
145c7a68094a5
152e57aa44cd8
hex18d2010fa99

1705640000153 has 2 divisors, whose sum is σ = 1705640000154. Its totient is φ = 1705640000152.

The previous prime is 1705640000149. The next prime is 1705640000173. The reversal of 1705640000153 is 3510000465071.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1321285878784 + 384354121369 = 1149472^2 + 619963^2 .

It is an emirp because it is prime and its reverse (3510000465071) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1705640000153 - 22 = 1705640000149 is a prime.

It is not a weakly prime, because it can be changed into another prime (1705640000173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 852820000076 + 852820000077.

It is an arithmetic number, because the mean of its divisors is an integer number (852820000077).

Almost surely, 21705640000153 is an apocalyptic number.

It is an amenable number.

1705640000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1705640000153 is an equidigital number, since it uses as much as digits as its factorization.

1705640000153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12600, while the sum is 32.

The spelling of 1705640000153 in words is "one trillion, seven hundred five billion, six hundred forty million, one hundred fifty-three", and thus it is an aban number.