Base | Representation |
---|---|
bin | 100110111000011110101010… |
… | …111111010111100101101011 |
3 | 211102111002221021100021000122 |
4 | 212320132222333113211223 |
5 | 134403234304324104101 |
6 | 1403411305531353455 |
7 | 51006563445336323 |
oct | 4670365277274553 |
9 | 742432837307018 |
10 | 171006991628651 |
11 | 4a5407266a4292 |
12 | 1721a3735b288b |
13 | 7455b7577cc49 |
14 | 3032ad549c283 |
15 | 14b843e74051b |
hex | 9b87aafd796b |
171006991628651 has 2 divisors, whose sum is σ = 171006991628652. Its totient is φ = 171006991628650.
The previous prime is 171006991628617. The next prime is 171006991628653. The reversal of 171006991628651 is 156826199600171.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 171006991628651 - 218 = 171006991366507 is a prime.
Together with 171006991628653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (171006991628653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85503495814325 + 85503495814326.
It is an arithmetic number, because the mean of its divisors is an integer number (85503495814326).
Almost surely, 2171006991628651 is an apocalyptic number.
171006991628651 is a deficient number, since it is larger than the sum of its proper divisors (1).
171006991628651 is an equidigital number, since it uses as much as digits as its factorization.
171006991628651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 62.
The spelling of 171006991628651 in words is "one hundred seventy-one trillion, six billion, nine hundred ninety-one million, six hundred twenty-eight thousand, six hundred fifty-one".
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