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171120452130083 is a prime number
BaseRepresentation
bin100110111010001000010101…
…110000110101010100100011
3211102212221210112021220221102
4212322020111300311110203
5134412114141221130313
61403535352255545015
751021021216600251
oct4672102560652443
9742787715256842
10171120452130083
114a58485a143335
121723835922b16b
137463787b96c21
1430383ba0bb5d1
1514bb380541a58
hex9ba215c35523

171120452130083 has 2 divisors, whose sum is σ = 171120452130084. Its totient is φ = 171120452130082.

The previous prime is 171120452130031. The next prime is 171120452130193. The reversal of 171120452130083 is 380031254021171.

It is a weak prime.

It is an emirp because it is prime and its reverse (380031254021171) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 171120452130083 - 220 = 171120451081507 is a prime.

It is not a weakly prime, because it can be changed into another prime (171120452133083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85560226065041 + 85560226065042.

It is an arithmetic number, because the mean of its divisors is an integer number (85560226065042).

Almost surely, 2171120452130083 is an apocalyptic number.

171120452130083 is a deficient number, since it is larger than the sum of its proper divisors (1).

171120452130083 is an equidigital number, since it uses as much as digits as its factorization.

171120452130083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 171120452130083 in words is "one hundred seventy-one trillion, one hundred twenty billion, four hundred fifty-two million, one hundred thirty thousand, eighty-three".