Base | Representation |
---|---|
bin | 11111111000001100… |
… | …10001010100100001 |
3 | 1122011201202210212121 |
4 | 33330012101110201 |
5 | 240022241413004 |
6 | 11510125024241 |
7 | 1144053014644 |
oct | 177406212441 |
9 | 48151683777 |
10 | 17114404129 |
11 | 72926a9149 |
12 | 33976b5081 |
13 | 17c990b264 |
14 | b84d7da5b |
15 | 6a2774854 |
hex | 3fc191521 |
17114404129 has 2 divisors, whose sum is σ = 17114404130. Its totient is φ = 17114404128.
The previous prime is 17114404063. The next prime is 17114404141. The reversal of 17114404129 is 92140441171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16320573504 + 793830625 = 127752^2 + 28175^2 .
It is an emirp because it is prime and its reverse (92140441171) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 17114404129 - 27 = 17114404001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 17114404094 and 17114404103.
It is not a weakly prime, because it can be changed into another prime (17114404159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8557202064 + 8557202065.
It is an arithmetic number, because the mean of its divisors is an integer number (8557202065).
Almost surely, 217114404129 is an apocalyptic number.
It is an amenable number.
17114404129 is a deficient number, since it is larger than the sum of its proper divisors (1).
17114404129 is an equidigital number, since it uses as much as digits as its factorization.
17114404129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 34.
The spelling of 17114404129 in words is "seventeen billion, one hundred fourteen million, four hundred four thousand, one hundred twenty-nine".
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