Search a number
-
+
171153114688397 is a prime number
BaseRepresentation
bin100110111010100110110000…
…100110100110101110001101
3211110000002002211122210200102
4212322212300212212232031
5134413133034330012042
61404002353323540445
751023255510010632
oct4672466046465615
9743002084583612
10171153114688397
114a5976a031a886
121724275398a725
137466891a664ca
143039bd7db0189
1514bc142ca6b32
hex9ba9b09a6b8d

171153114688397 has 2 divisors, whose sum is σ = 171153114688398. Its totient is φ = 171153114688396.

The previous prime is 171153114688289. The next prime is 171153114688441. The reversal of 171153114688397 is 793886411351171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143513427724681 + 27639686963716 = 11979709^2 + 5257346^2 .

It is an emirp because it is prime and its reverse (793886411351171) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 171153114688397 - 218 = 171153114426253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171153114688097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85576557344198 + 85576557344199.

It is an arithmetic number, because the mean of its divisors is an integer number (85576557344199).

Almost surely, 2171153114688397 is an apocalyptic number.

It is an amenable number.

171153114688397 is a deficient number, since it is larger than the sum of its proper divisors (1).

171153114688397 is an equidigital number, since it uses as much as digits as its factorization.

171153114688397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30481920, while the sum is 65.

The spelling of 171153114688397 in words is "one hundred seventy-one trillion, one hundred fifty-three billion, one hundred fourteen million, six hundred eighty-eight thousand, three hundred ninety-seven".