Base | Representation |
---|---|
bin | 1001111101110001011… |
… | …0111101100111111010 |
3 | 121100220021101021021121 |
4 | 2133130112331213322 |
5 | 10301104341403032 |
6 | 210352025455454 |
7 | 15240341131333 |
oct | 2373426754772 |
9 | 540807337247 |
10 | 171200731642 |
11 | 66673393676 |
12 | 2921a94158a |
13 | 131b4946595 |
14 | 840131728a |
15 | 46bee7ca97 |
hex | 27dc5bd9fa |
171200731642 has 4 divisors (see below), whose sum is σ = 256801097466. Its totient is φ = 85600365820.
The previous prime is 171200731627. The next prime is 171200731643. The reversal of 171200731642 is 246137002171.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 246137002171 = 47 ⋅5236957493.
It can be written as a sum of positive squares in only one way, i.e., 168928398081 + 2272333561 = 411009^2 + 47669^2 .
It is a super-2 number, since 2×1712007316422 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 171200731598 and 171200731607.
It is not an unprimeable number, because it can be changed into a prime (171200731643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42800182909 + ... + 42800182912.
Almost surely, 2171200731642 is an apocalyptic number.
171200731642 is a deficient number, since it is larger than the sum of its proper divisors (85600365824).
171200731642 is an equidigital number, since it uses as much as digits as its factorization.
171200731642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85600365823.
The product of its (nonzero) digits is 14112, while the sum is 34.
The spelling of 171200731642 in words is "one hundred seventy-one billion, two hundred million, seven hundred thirty-one thousand, six hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •