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171212275660117 is a prime number
BaseRepresentation
bin100110111011011101110110…
…110111110011010101010101
3211110012201210212110120000011
4212323131312313303111111
5134420120220032110432
61404045500020520221
751030451540662016
oct4673356667632525
9743181725416004
10171212275660117
114a60a79a12a53a
1217252104850071
13746c32c727353
14303ca0b25900d
1514bd956a23847
hex9bb776df3555

171212275660117 has 2 divisors, whose sum is σ = 171212275660118. Its totient is φ = 171212275660116.

The previous prime is 171212275660033. The next prime is 171212275660189. The reversal of 171212275660117 is 711066572212171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 156935901088836 + 14276374571281 = 12527406^2 + 3778409^2 .

It is a cyclic number.

It is not a de Polignac number, because 171212275660117 - 223 = 171212267271509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171212275660817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85606137830058 + 85606137830059.

It is an arithmetic number, because the mean of its divisors is an integer number (85606137830059).

Almost surely, 2171212275660117 is an apocalyptic number.

It is an amenable number.

171212275660117 is a deficient number, since it is larger than the sum of its proper divisors (1).

171212275660117 is an equidigital number, since it uses as much as digits as its factorization.

171212275660117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 493920, while the sum is 49.

The spelling of 171212275660117 in words is "one hundred seventy-one trillion, two hundred twelve billion, two hundred seventy-five million, six hundred sixty thousand, one hundred seventeen".