Base | Representation |
---|---|
bin | 11000111011011011100… |
… | …010111011100010000101 |
3 | 20001202202111220111022222 |
4 | 120323123202323202011 |
5 | 211031342032211403 |
6 | 3350551145102125 |
7 | 234523504504154 |
oct | 30733342734205 |
9 | 6052674814288 |
10 | 1713080350853 |
11 | 60057121a803 |
12 | 23800b187945 |
13 | c570965b451 |
14 | 5ccb0a3159b |
15 | 2e863d43338 |
hex | 18edb8bb885 |
1713080350853 has 2 divisors, whose sum is σ = 1713080350854. Its totient is φ = 1713080350852.
The previous prime is 1713080350829. The next prime is 1713080350913. The reversal of 1713080350853 is 3580530803171.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1252917558244 + 460162792609 = 1119338^2 + 678353^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1713080350853 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1713080950853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 856540175426 + 856540175427.
It is an arithmetic number, because the mean of its divisors is an integer number (856540175427).
Almost surely, 21713080350853 is an apocalyptic number.
It is an amenable number.
1713080350853 is a deficient number, since it is larger than the sum of its proper divisors (1).
1713080350853 is an equidigital number, since it uses as much as digits as its factorization.
1713080350853 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 44.
The spelling of 1713080350853 in words is "one trillion, seven hundred thirteen billion, eighty million, three hundred fifty thousand, eight hundred fifty-three".
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