Base | Representation |
---|---|
bin | 10100011010111… |
… | …11101111001111 |
3 | 102221100110011222 |
4 | 22031133233033 |
5 | 322323410111 |
6 | 24555433555 |
7 | 4150053104 |
oct | 1215375717 |
9 | 387313158 |
10 | 171310031 |
11 | 88777842 |
12 | 494558bb |
13 | 296506a9 |
14 | 18a74aab |
15 | 1008d7db |
hex | a35fbcf |
171310031 has 2 divisors, whose sum is σ = 171310032. Its totient is φ = 171310030.
The previous prime is 171309997. The next prime is 171310063. The reversal of 171310031 is 130013171.
It is a strong prime.
It is an emirp because it is prime and its reverse (130013171) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 171310031 - 26 = 171309967 is a prime.
It is a super-2 number, since 2×1713100312 = 58694253442441922, which contains 22 as substring.
It is a Sophie Germain prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 171309991 and 171310009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (171310331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85655015 + 85655016.
It is an arithmetic number, because the mean of its divisors is an integer number (85655016).
Almost surely, 2171310031 is an apocalyptic number.
171310031 is a deficient number, since it is larger than the sum of its proper divisors (1).
171310031 is an equidigital number, since it uses as much as digits as its factorization.
171310031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63, while the sum is 17.
The square root of 171310031 is about 13088.5457939375. The cubic root of 171310031 is about 555.3851515882.
The spelling of 171310031 in words is "one hundred seventy-one million, three hundred ten thousand, thirty-one".
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