Search a number
-
+
17133393305513 is a prime number
BaseRepresentation
bin1111100101010010110111…
…0100100101111110101001
32020122221021122020020220102
43321110231310211332221
54221203142141234023
6100234550000035145
73415563313115042
oct371245564457651
966587248206812
1017133393305513
11550625a944111
121b08696902ab5
13973897679354
144333913778c9
151eaa2b339628
hexf952dd25fa9

17133393305513 has 2 divisors, whose sum is σ = 17133393305514. Its totient is φ = 17133393305512.

The previous prime is 17133393305473. The next prime is 17133393305533. The reversal of 17133393305513 is 31550339333171.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16305096733849 + 828296571664 = 4037957^2 + 910108^2 .

It is an emirp because it is prime and its reverse (31550339333171) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17133393305513 is a prime.

It is a super-2 number, since 2×171333933055132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (17133393305533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8566696652756 + 8566696652757.

It is an arithmetic number, because the mean of its divisors is an integer number (8566696652757).

Almost surely, 217133393305513 is an apocalyptic number.

It is an amenable number.

17133393305513 is a deficient number, since it is larger than the sum of its proper divisors (1).

17133393305513 is an equidigital number, since it uses as much as digits as its factorization.

17133393305513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1148175, while the sum is 47.

The spelling of 17133393305513 in words is "seventeen trillion, one hundred thirty-three billion, three hundred ninety-three million, three hundred five thousand, five hundred thirteen".