Base | Representation |
---|---|
bin | 11111111010011101… |
… | …10111000100101010 |
3 | 1122020001120120202102 |
4 | 33331032313010222 |
5 | 240042124330010 |
6 | 11512044533402 |
7 | 1144403531042 |
oct | 177516670452 |
9 | 48201516672 |
10 | 17133433130 |
11 | 72a24159a0 |
12 | 33a1b51262 |
13 | 1800841718 |
14 | b876d4722 |
15 | 6a4282ba5 |
hex | 3fd3b712a |
17133433130 has 32 divisors (see below), whose sum is σ = 33653128320. Its totient is φ = 6228617920.
The previous prime is 17133433123. The next prime is 17133433159. The reversal of 17133433130 is 3133433171.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 17133433093 and 17133433102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 419267 + ... + 458313.
It is an arithmetic number, because the mean of its divisors is an integer number (1051660260).
Almost surely, 217133433130 is an apocalyptic number.
17133433130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
17133433130 is a deficient number, since it is larger than the sum of its proper divisors (16519695190).
17133433130 is a wasteful number, since it uses less digits than its factorization.
17133433130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43054.
The product of its (nonzero) digits is 6804, while the sum is 29.
The spelling of 17133433130 in words is "seventeen billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred thirty".
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