Base | Representation |
---|---|
bin | 1111100101010110000110… |
… | …1111010011000101100001 |
3 | 2020200000112100020000111102 |
4 | 3321111201233103011201 |
5 | 4221211433132121031 |
6 | 100235212233124145 |
7 | 3415624020533531 |
oct | 371254157230541 |
9 | 66600470200442 |
10 | 17134264332641 |
11 | 5506667587745 |
12 | 1b0889a559655 |
13 | 9739a5c6a411 |
14 | 433434d114c1 |
15 | 1eaa7ca417cb |
hex | f9561bd3161 |
17134264332641 has 2 divisors, whose sum is σ = 17134264332642. Its totient is φ = 17134264332640.
The previous prime is 17134264332569. The next prime is 17134264332671. The reversal of 17134264332641 is 14623346243171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9703848010000 + 7430416322641 = 3115100^2 + 2725879^2 .
It is a cyclic number.
It is not a de Polignac number, because 17134264332641 - 222 = 17134260138337 is a prime.
It is not a weakly prime, because it can be changed into another prime (17134264332671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8567132166320 + 8567132166321.
It is an arithmetic number, because the mean of its divisors is an integer number (8567132166321).
Almost surely, 217134264332641 is an apocalyptic number.
It is an amenable number.
17134264332641 is a deficient number, since it is larger than the sum of its proper divisors (1).
17134264332641 is an equidigital number, since it uses as much as digits as its factorization.
17134264332641 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1741824, while the sum is 47.
The spelling of 17134264332641 in words is "seventeen trillion, one hundred thirty-four billion, two hundred sixty-four million, three hundred thirty-two thousand, six hundred forty-one".
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