Base | Representation |
---|---|
bin | 11111111010101101… |
… | …11100011001110001 |
3 | 1122020012120020110021 |
4 | 33331112330121301 |
5 | 240043200131423 |
6 | 11512202203441 |
7 | 1144430534611 |
oct | 177526743161 |
9 | 48205506407 |
10 | 17135552113 |
11 | 72a3632a19 |
12 | 33a27b3581 |
13 | 1801104064 |
14 | b87ac6a41 |
15 | 6a455095d |
hex | 3fd5bc671 |
17135552113 has 2 divisors, whose sum is σ = 17135552114. Its totient is φ = 17135552112.
The previous prime is 17135552051. The next prime is 17135552131. The reversal of 17135552113 is 31125553171.
Together with next prime (17135552131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14588533089 + 2547019024 = 120783^2 + 50468^2 .
It is a cyclic number.
It is not a de Polignac number, because 17135552113 - 225 = 17101997681 is a prime.
It is not a weakly prime, because it can be changed into another prime (17135552153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8567776056 + 8567776057.
It is an arithmetic number, because the mean of its divisors is an integer number (8567776057).
Almost surely, 217135552113 is an apocalyptic number.
It is an amenable number.
17135552113 is a deficient number, since it is larger than the sum of its proper divisors (1).
17135552113 is an equidigital number, since it uses as much as digits as its factorization.
17135552113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15750, while the sum is 34.
The spelling of 17135552113 in words is "seventeen billion, one hundred thirty-five million, five hundred fifty-two thousand, one hundred thirteen".
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