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17139054131 is a prime number
BaseRepresentation
bin11111111011001000…
…10011011000110011
31122020110011011022122
433331210103120303
5240100044213011
611512405224455
71144502361563
oct177544233063
948213134278
1017139054131
1172a5605051
1233a3a0212b
131801a5c064
14b88358da3
156a49e33db
hex3fd913633

17139054131 has 2 divisors, whose sum is σ = 17139054132. Its totient is φ = 17139054130.

The previous prime is 17139054109. The next prime is 17139054157. The reversal of 17139054131 is 13145093171.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17139054131 is a prime.

It is a super-2 number, since 2×171390541312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 17139054091 and 17139054100.

It is not a weakly prime, because it can be changed into another prime (17139054731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8569527065 + 8569527066.

It is an arithmetic number, because the mean of its divisors is an integer number (8569527066).

Almost surely, 217139054131 is an apocalyptic number.

17139054131 is a deficient number, since it is larger than the sum of its proper divisors (1).

17139054131 is an equidigital number, since it uses as much as digits as its factorization.

17139054131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11340, while the sum is 35.

The spelling of 17139054131 in words is "seventeen billion, one hundred thirty-nine million, fifty-four thousand, one hundred thirty-one".