Base | Representation |
---|---|
bin | 110011000101010… |
… | …0011011111100101 |
3 | 11102110021101202122 |
4 | 1212022203133211 |
5 | 12002243332403 |
6 | 442025515325 |
7 | 60322060325 |
oct | 14612433745 |
9 | 4373241678 |
10 | 1714042853 |
11 | 7aa594846 |
12 | 3ba042b45 |
13 | 214155353 |
14 | 1238dd285 |
15 | a0729838 |
hex | 662a37e5 |
1714042853 has 2 divisors, whose sum is σ = 1714042854. Its totient is φ = 1714042852.
The previous prime is 1714042829. The next prime is 1714042861. The reversal of 1714042853 is 3582404171.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1680426049 + 33616804 = 40993^2 + 5798^2 .
It is a cyclic number.
It is not a de Polignac number, because 1714042853 - 26 = 1714042789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1714042553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 857021426 + 857021427.
It is an arithmetic number, because the mean of its divisors is an integer number (857021427).
Almost surely, 21714042853 is an apocalyptic number.
It is an amenable number.
1714042853 is a deficient number, since it is larger than the sum of its proper divisors (1).
1714042853 is an equidigital number, since it uses as much as digits as its factorization.
1714042853 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26880, while the sum is 35.
The square root of 1714042853 is about 41401.0006280041. Note that the first 3 decimals coincide. The cubic root of 1714042853 is about 1196.7604411874.
The spelling of 1714042853 in words is "one billion, seven hundred fourteen million, forty-two thousand, eight hundred fifty-three".
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