Base | Representation |
---|---|
bin | 11000111111000111100… |
… | …011111111011100111111 |
3 | 20002010222110210011012011 |
4 | 120333013203333130333 |
5 | 211112444223131111 |
6 | 3352444115152051 |
7 | 235023565426363 |
oct | 30770743773477 |
9 | 6063873704164 |
10 | 1717040052031 |
11 | 602213389917 |
12 | 2389352a5627 |
13 | c5bbab102b5 |
14 | 5d1688952a3 |
15 | 2e9e67a8021 |
hex | 18fc78ff73f |
1717040052031 has 2 divisors, whose sum is σ = 1717040052032. Its totient is φ = 1717040052030.
The previous prime is 1717040051999. The next prime is 1717040052071. The reversal of 1717040052031 is 1302500407171.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1717040052031 - 25 = 1717040051999 is a prime.
It is a super-2 number, since 2×17170400520312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1717040051984 and 1717040052002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1717040052071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 858520026015 + 858520026016.
It is an arithmetic number, because the mean of its divisors is an integer number (858520026016).
Almost surely, 21717040052031 is an apocalyptic number.
1717040052031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1717040052031 is an equidigital number, since it uses as much as digits as its factorization.
1717040052031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5880, while the sum is 31.
The spelling of 1717040052031 in words is "one trillion, seven hundred seventeen billion, forty million, fifty-two thousand, thirty-one".
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