Search a number
-
+
171755754101213 is a prime number
BaseRepresentation
bin100111000011011000000000…
…101101100001100111011101
3211112010200121211000220212212
4213003120000231201213131
5140003021241022214323
61405143300522010205
751114641462341022
oct4703300055414735
9745120554026785
10171755754101213
114a7aa22a588287
121731b4ba646965
1374ab662486139
14305b0469d5549
1514ccb646dcb78
hex9c3600b619dd

171755754101213 has 2 divisors, whose sum is σ = 171755754101214. Its totient is φ = 171755754101212.

The previous prime is 171755754101209. The next prime is 171755754101279. The reversal of 171755754101213 is 312101457557171.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 149810305048804 + 21945449052409 = 12239702^2 + 4684597^2 .

It is a cyclic number.

It is not a de Polignac number, because 171755754101213 - 22 = 171755754101209 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (171755754151213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 85877877050606 + 85877877050607.

It is an arithmetic number, because the mean of its divisors is an integer number (85877877050607).

Almost surely, 2171755754101213 is an apocalyptic number.

It is an amenable number.

171755754101213 is a deficient number, since it is larger than the sum of its proper divisors (1).

171755754101213 is an equidigital number, since it uses as much as digits as its factorization.

171755754101213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1029000, while the sum is 50.

The spelling of 171755754101213 in words is "one hundred seventy-one trillion, seven hundred fifty-five billion, seven hundred fifty-four million, one hundred one thousand, two hundred thirteen".