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172013323 is a prime number
BaseRepresentation
bin10100100000010…
…11011100001011
3102222200011220211
422100023130023
5323013411243
625022501551
74156042366
oct1220133413
9388604824
10172013323
1189108179
12497348b7
1329838841
1418bb90dd
151017bd9d
hexa40b70b

172013323 has 2 divisors, whose sum is σ = 172013324. Its totient is φ = 172013322.

The previous prime is 172013269. The next prime is 172013339. The reversal of 172013323 is 323310271.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (323310271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 172013323 - 213 = 172005131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 172013294 and 172013303.

It is not a weakly prime, because it can be changed into another prime (172013353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86006661 + 86006662.

It is an arithmetic number, because the mean of its divisors is an integer number (86006662).

Almost surely, 2172013323 is an apocalyptic number.

172013323 is a deficient number, since it is larger than the sum of its proper divisors (1).

172013323 is an equidigital number, since it uses as much as digits as its factorization.

172013323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 22.

The square root of 172013323 is about 13115.3849733815. The cubic root of 172013323 is about 556.1441354229.

Adding to 172013323 its reverse (323310271), we get a palindrome (495323594).

The spelling of 172013323 in words is "one hundred seventy-two million, thirteen thousand, three hundred twenty-three".