17213140253 has 2 divisors, whose sum is σ = 17213140254. Its totient is φ = 17213140252.

The previous prime is 17213140213. The next prime is 17213140277. The reversal of 17213140253 is 35204131271.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12428236324 + 4784903929 = 111482^2 + 69173^2 .

It is an emirp because it is prime and its reverse (35204131271) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-17213140253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17213140213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8606570126 + 8606570127.

It is an arithmetic number, because the mean of its divisors is an integer number (8606570127).

Almost surely, 2^17213140253 is an apocalyptic number.

It is an amenable number.

17213140253 is a deficient number, since it is larger than the sum of its proper divisors (1).

17213140253 is an equidigital number, since it uses as much as digits as its factorization.

17213140253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 29.

The spelling of 17213140253 in words is "seventeen billion, two hundred thirteen million, one hundred forty thousand, two hundred fifty-three".