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17214120000 = 26355471123
BaseRepresentation
bin10000000010000010…
…101010000001000000
31122102200101220100000
4100002002222001000
5240223303320000
611524050200000
71146403414530
oct200202520100
948380356300
1017214120000
117333a16160
123404b83000
13181448262c
14b942d94c0
156ab3c0000
hex4020aa040

17214120000 has 1680 divisors, whose sum is σ = 83183772672. Its totient is φ = 3421440000.

The previous prime is 17214119971. The next prime is 17214120013. The reversal of 17214120000 is 2141271.

It is a tau number, because it is divible by the number of its divisors (1680).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 748439989 + ... + 748440011.

Almost surely, 217214120000 is an apocalyptic number.

17214120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 17214120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (41591886336).

17214120000 is an abundant number, since it is smaller than the sum of its proper divisors (65969652672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

17214120000 is an equidigital number, since it uses as much as digits as its factorization.

17214120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88 (or 51 counting only the distinct ones).

The product of its (nonzero) digits is 112, while the sum is 18.

Adding to 17214120000 its reverse (2141271), we get a palindrome (17216261271).

The spelling of 17214120000 in words is "seventeen billion, two hundred fourteen million, one hundred twenty thousand".