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172145530093 is a prime number
BaseRepresentation
bin1010000001010010101…
…1000101010011101101
3121110100010012000002211
42200110223011103231
510310023223430333
6211025500050421
715302632601635
oct2402453052355
9543303160084
10172145530093
1167008733739
1229443233a11
13133055c6914
1484909b56c5
154727da7ecd
hex2814ac54ed

172145530093 has 2 divisors, whose sum is σ = 172145530094. Its totient is φ = 172145530092.

The previous prime is 172145530061. The next prime is 172145530099. The reversal of 172145530093 is 390035541271.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137423679849 + 34721850244 = 370707^2 + 186338^2 .

It is an emirp because it is prime and its reverse (390035541271) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 172145530093 - 25 = 172145530061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (172145530099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86072765046 + 86072765047.

It is an arithmetic number, because the mean of its divisors is an integer number (86072765047).

Almost surely, 2172145530093 is an apocalyptic number.

It is an amenable number.

172145530093 is a deficient number, since it is larger than the sum of its proper divisors (1).

172145530093 is an equidigital number, since it uses as much as digits as its factorization.

172145530093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 40.

The spelling of 172145530093 in words is "one hundred seventy-two billion, one hundred forty-five million, five hundred thirty thousand, ninety-three".