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172217667040093 is a prime number
BaseRepresentation
bin100111001010000110001100…
…110111100011001101011101
3211120202211220022201110110001
4213022012030313203031131
5140033103240230240333
61410135412023214301
751163213222466023
oct4712061467431535
9746684808643401
10172217667040093
114a96811437aa64
1217394b302a7391
13751309696564c
143075545722713
1514d9b9b750b7d
hex9ca18cde335d

172217667040093 has 2 divisors, whose sum is σ = 172217667040094. Its totient is φ = 172217667040092.

The previous prime is 172217667040073. The next prime is 172217667040187. The reversal of 172217667040093 is 390040766712271.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154419840790084 + 17797826250009 = 12426578^2 + 4218747^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-172217667040093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (172217667040043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 86108833520046 + 86108833520047.

It is an arithmetic number, because the mean of its divisors is an integer number (86108833520047).

Almost surely, 2172217667040093 is an apocalyptic number.

It is an amenable number.

172217667040093 is a deficient number, since it is larger than the sum of its proper divisors (1).

172217667040093 is an equidigital number, since it uses as much as digits as its factorization.

172217667040093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5334336, while the sum is 55.

The spelling of 172217667040093 in words is "one hundred seventy-two trillion, two hundred seventeen billion, six hundred sixty-seven million, forty thousand, ninety-three".