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17242585379471 is a prime number
BaseRepresentation
bin1111101011101001101000…
…1011010011001010001111
32021001101010102101100002202
43322322122023103022033
54230000303324120341
6100401045005112115
73426510224331014
oct372723213231217
967041112340082
1017242585379471
1155485a2a2a451
121b2588ab5863b
13980c796797ba
1443878d12b70b
151ed7bc54179b
hexfae9a2d328f

17242585379471 has 2 divisors, whose sum is σ = 17242585379472. Its totient is φ = 17242585379470.

The previous prime is 17242585379449. The next prime is 17242585379497. The reversal of 17242585379471 is 17497358524271.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17242585379471 is a prime.

It is a super-3 number, since 3×172425853794713 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 17242585379398 and 17242585379407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17242585379401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8621292689735 + 8621292689736.

It is an arithmetic number, because the mean of its divisors is an integer number (8621292689736).

Almost surely, 217242585379471 is an apocalyptic number.

17242585379471 is a deficient number, since it is larger than the sum of its proper divisors (1).

17242585379471 is an equidigital number, since it uses as much as digits as its factorization.

17242585379471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 118540800, while the sum is 65.

The spelling of 17242585379471 in words is "seventeen trillion, two hundred forty-two billion, five hundred eighty-five million, three hundred seventy-nine thousand, four hundred seventy-one".