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17251329113 is a prime number
BaseRepresentation
bin10000000100010000…
…100110010001011001
31122112021102022122022
4100010100212101121
5240312320012423
611531455504225
71150334610104
oct200420462131
948467368568
1017251329113
117352a1a997
123415528075
13181c0aca65
14b9922373b
156ae7bedc8
hex404426459

17251329113 has 2 divisors, whose sum is σ = 17251329114. Its totient is φ = 17251329112.

The previous prime is 17251329107. The next prime is 17251329119. The reversal of 17251329113 is 31192315271.

It is a balanced prime because it is at equal distance from previous prime (17251329107) and next prime (17251329119).

It can be written as a sum of positive squares in only one way, i.e., 17189045449 + 62283664 = 131107^2 + 7892^2 .

It is a cyclic number.

It is not a de Polignac number, because 17251329113 - 26 = 17251329049 is a prime.

It is not a weakly prime, because it can be changed into another prime (17251329119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8625664556 + 8625664557.

It is an arithmetic number, because the mean of its divisors is an integer number (8625664557).

Almost surely, 217251329113 is an apocalyptic number.

It is an amenable number.

17251329113 is a deficient number, since it is larger than the sum of its proper divisors (1).

17251329113 is an equidigital number, since it uses as much as digits as its factorization.

17251329113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11340, while the sum is 35.

The spelling of 17251329113 in words is "seventeen billion, two hundred fifty-one million, three hundred twenty-nine thousand, one hundred thirteen".