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1738025628149 is a prime number
BaseRepresentation
bin11001010010101010011…
…001100111000111110101
320011011010222211212201002
4121102222121213013311
5211433434030100044
63410234333013045
7236365616041136
oct31225231470765
96134128755632
101738025628149
1161010217a858
12240a11324185
13c7b83744a65
1460199a11c8d
1530323d0674e
hex194aa6671f5

1738025628149 has 2 divisors, whose sum is σ = 1738025628150. Its totient is φ = 1738025628148.

The previous prime is 1738025628113. The next prime is 1738025628161. The reversal of 1738025628149 is 9418265208371.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1091569427524 + 646456200625 = 1044782^2 + 804025^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1738025628149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1738025628094 and 1738025628103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1738025628109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 869012814074 + 869012814075.

It is an arithmetic number, because the mean of its divisors is an integer number (869012814075).

It is a 2-persistent number, because it is pandigital, and so is 2⋅1738025628149 = 3476051256298, but 3⋅1738025628149 = 5214076884447 is not.

Almost surely, 21738025628149 is an apocalyptic number.

It is an amenable number.

1738025628149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1738025628149 is an equidigital number, since it uses as much as digits as its factorization.

1738025628149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 56.

The spelling of 1738025628149 in words is "one trillion, seven hundred thirty-eight billion, twenty-five million, six hundred twenty-eight thousand, one hundred forty-nine".