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1740313483 is a prime number
BaseRepresentation
bin110011110111011…
…0001001110001011
311111021201002021221
41213232301032023
512031010012413
6444404542511
761061264146
oct14756611613
94437632257
101740313483
118133a8307
124069b1a37
132197229bc
141271bb05d
15a2bb868d
hex67bb138b

1740313483 has 2 divisors, whose sum is σ = 1740313484. Its totient is φ = 1740313482.

The previous prime is 1740313451. The next prime is 1740313489. The reversal of 1740313483 is 3843130471.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1740313483 - 25 = 1740313451 is a prime.

It is a super-2 number, since 2×17403134832 = 6057382038223182578, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1740313489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 870156741 + 870156742.

It is an arithmetic number, because the mean of its divisors is an integer number (870156742).

Almost surely, 21740313483 is an apocalyptic number.

1740313483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1740313483 is an equidigital number, since it uses as much as digits as its factorization.

1740313483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 34.

The square root of 1740313483 is about 41717.0646498528. The cubic root of 1740313483 is about 1202.8435995823.

The spelling of 1740313483 in words is "one billion, seven hundred forty million, three hundred thirteen thousand, four hundred eighty-three".