Base | Representation |
---|---|
bin | 11001010101101110010… |
… | …010111001000110001111 |
3 | 20011110122001010002020022 |
4 | 121111232102321012033 |
5 | 212012201410413403 |
6 | 3411540415412355 |
7 | 236543224331366 |
oct | 31255622710617 |
9 | 6143561102208 |
10 | 1741312201103 |
11 | 611539383752 |
12 | 241589b240bb |
13 | c8288605697 |
14 | 603cc2d47dd |
15 | 30467605d38 |
hex | 1956e4b918f |
1741312201103 has 2 divisors, whose sum is σ = 1741312201104. Its totient is φ = 1741312201102.
The previous prime is 1741312201093. The next prime is 1741312201207. The reversal of 1741312201103 is 3011022131471.
It is a weak prime.
It is an emirp because it is prime and its reverse (3011022131471) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1741312201103 - 24 = 1741312201087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1741312201903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 870656100551 + 870656100552.
It is an arithmetic number, because the mean of its divisors is an integer number (870656100552).
Almost surely, 21741312201103 is an apocalyptic number.
1741312201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1741312201103 is an equidigital number, since it uses as much as digits as its factorization.
1741312201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 1741312201103 its reverse (3011022131471), we get a palindrome (4752334332574).
The spelling of 1741312201103 in words is "one trillion, seven hundred forty-one billion, three hundred twelve million, two hundred one thousand, one hundred three".
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