Search a number
-
+
174400518212113 is a prime number
BaseRepresentation
bin100111101001110111001000…
…111011111100101000010001
3211212111112012222022021101111
4213221313020323330220101
5140324334230130241423
61414530254135333321
751510010264351054
oct4751671073745021
9755445188267344
10174400518212113
1150629931a11736
1217687ba4821241
137640b8a74719b
14310d05c912a9b
1515268573cd60d
hex9e9dc8efca11

174400518212113 has 2 divisors, whose sum is σ = 174400518212114. Its totient is φ = 174400518212112.

The previous prime is 174400518212057. The next prime is 174400518212149. The reversal of 174400518212113 is 311212815004471.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 159661622089984 + 14738896122129 = 12635728^2 + 3839127^2 .

It is a cyclic number.

It is not a de Polignac number, because 174400518212113 - 245 = 139216146123281 is a prime.

It is not a weakly prime, because it can be changed into another prime (174400518222113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 87200259106056 + 87200259106057.

It is an arithmetic number, because the mean of its divisors is an integer number (87200259106057).

Almost surely, 2174400518212113 is an apocalyptic number.

It is an amenable number.

174400518212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

174400518212113 is an equidigital number, since it uses as much as digits as its factorization.

174400518212113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53760, while the sum is 40.

The spelling of 174400518212113 in words is "one hundred seventy-four trillion, four hundred billion, five hundred eighteen million, two hundred twelve thousand, one hundred thirteen".