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17448142013 is a prime number
BaseRepresentation
bin10000001111111111…
…011000010010111101
31200000222202110011222
4100033333120102331
5241213211021023
612003210123125
71155244521461
oct201777302275
950028673158
1017448142013
117444026385
12346b4204a5
131850abc4b3
14bb74164a1
156c1be9cc8
hex40ffd84bd

17448142013 has 2 divisors, whose sum is σ = 17448142014. Its totient is φ = 17448142012.

The previous prime is 17448141983. The next prime is 17448142027. The reversal of 17448142013 is 31024184471.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14760549049 + 2687592964 = 121493^2 + 51842^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17448142013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (17448142043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8724071006 + 8724071007.

It is an arithmetic number, because the mean of its divisors is an integer number (8724071007).

Almost surely, 217448142013 is an apocalyptic number.

It is an amenable number.

17448142013 is a deficient number, since it is larger than the sum of its proper divisors (1).

17448142013 is an equidigital number, since it uses as much as digits as its factorization.

17448142013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 35.

The spelling of 17448142013 in words is "seventeen billion, four hundred forty-eight million, one hundred forty-two thousand, thirteen".