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1764366113 is a prime number
BaseRepresentation
bin110100100101010…
…0001011100100001
311112221222002022002
41221022201130201
512103134203423
6451024253345
761502602346
oct15112413441
94487862262
101764366113
11825a36414
12412a71255
132216c4923
1412a47c7cd
15a4d6a228
hex692a1721

1764366113 has 2 divisors, whose sum is σ = 1764366114. Its totient is φ = 1764366112.

The previous prime is 1764366101. The next prime is 1764366139. The reversal of 1764366113 is 3116634671.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1545118864 + 219247249 = 39308^2 + 14807^2 .

It is an emirp because it is prime and its reverse (3116634671) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1764366113 is a prime.

It is a super-2 number, since 2×17643661132 = 6225975561405457538, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1764366143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 882183056 + 882183057.

It is an arithmetic number, because the mean of its divisors is an integer number (882183057).

Almost surely, 21764366113 is an apocalyptic number.

It is an amenable number.

1764366113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1764366113 is an equidigital number, since it uses as much as digits as its factorization.

1764366113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54432, while the sum is 38.

The square root of 1764366113 is about 42004.3582619709. The cubic root of 1764366113 is about 1208.3597091962.

The spelling of 1764366113 in words is "one billion, seven hundred sixty-four million, three hundred sixty-six thousand, one hundred thirteen".