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180042257548441 is a prime number
BaseRepresentation
bin101000111011111101011010…
…110011100100010010011001
3212121110212112111012102200101
4220323331122303210102121
5142044303020413022231
61434530134333135401
752631423660436361
oct5073753263442231
9777425474172611
10180042257548441
115240454676a972
121823948b92a561
13795cbb198b1a2
14326613db119a1
1515c34a3ec8661
hexa3bf5ace4499

180042257548441 has 2 divisors, whose sum is σ = 180042257548442. Its totient is φ = 180042257548440.

The previous prime is 180042257548339. The next prime is 180042257548487. The reversal of 180042257548441 is 144845752240081.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101688266083600 + 78353991464841 = 10084060^2 + 8851779^2 .

It is a cyclic number.

It is not a de Polignac number, because 180042257548441 - 223 = 180042249159833 is a prime.

It is not a weakly prime, because it can be changed into another prime (180042257548141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 90021128774220 + 90021128774221.

It is an arithmetic number, because the mean of its divisors is an integer number (90021128774221).

Almost surely, 2180042257548441 is an apocalyptic number.

It is an amenable number.

180042257548441 is a deficient number, since it is larger than the sum of its proper divisors (1).

180042257548441 is an equidigital number, since it uses as much as digits as its factorization.

180042257548441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11468800, while the sum is 55.

The spelling of 180042257548441 in words is "one hundred eighty trillion, forty-two billion, two hundred fifty-seven million, five hundred forty-eight thousand, four hundred forty-one".