Base | Representation |
---|---|
bin | 1000010001110001001001… |
… | …10101010000100100111011 |
3 | 2101110011022201101001112021 |
4 | 10020320210311100210323 |
5 | 4341213101432414010 |
6 | 102414111113055311 |
7 | 3556046416343212 |
oct | 410704465204473 |
9 | 71404281331467 |
10 | 18202689341755 |
11 | 5888798654746 |
12 | 205b9779b7537 |
13 | a20677292c19 |
14 | 46d02cb0a079 |
15 | 2187614a98da |
hex | 108e24d5093b |
18202689341755 has 32 divisors (see below), whose sum is σ = 23533606736640. Its totient is φ = 13471444990080.
The previous prime is 18202689341741. The next prime is 18202689341801. The reversal of 18202689341755 is 55714398620281.
It is a happy number.
It is not a de Polignac number, because 18202689341755 - 215 = 18202689308987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 18202689341693 and 18202689341702.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15457525 + ... + 16593385.
It is an arithmetic number, because the mean of its divisors is an integer number (735425210520).
It is a 1-persistent number, because it is pandigital, but 2⋅18202689341755 = 36405378683510 is not.
Almost surely, 218202689341755 is an apocalyptic number.
18202689341755 is a deficient number, since it is larger than the sum of its proper divisors (5330917394885).
18202689341755 is a wasteful number, since it uses less digits than its factorization.
18202689341755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1139851.
The product of its (nonzero) digits is 29030400, while the sum is 61.
The spelling of 18202689341755 in words is "eighteen trillion, two hundred two billion, six hundred eighty-nine million, three hundred forty-one thousand, seven hundred fifty-five".
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