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18202689341801 is a prime number
BaseRepresentation
bin1000010001110001001001…
…10101010000100101101001
32101110011022201101001120222
410020320210311100211221
54341213101432414201
6102414111113055425
73556046416343306
oct410704465204551
971404281331528
1018202689341801
115888798654788
12205b9779b7575
13a20677292c53
1446d02cb0a0ad
152187614a991b
hex108e24d50969

18202689341801 has 2 divisors, whose sum is σ = 18202689341802. Its totient is φ = 18202689341800.

The previous prime is 18202689341741. The next prime is 18202689341803. The reversal of 18202689341801 is 10814398620281.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9186476046400 + 9016213295401 = 3030920^2 + 3002701^2 .

It is a cyclic number.

It is not a de Polignac number, because 18202689341801 - 210 = 18202689340777 is a prime.

Together with 18202689341803, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (18202689341803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9101344670900 + 9101344670901.

It is an arithmetic number, because the mean of its divisors is an integer number (9101344670901).

Almost surely, 218202689341801 is an apocalyptic number.

It is an amenable number.

18202689341801 is a deficient number, since it is larger than the sum of its proper divisors (1).

18202689341801 is an equidigital number, since it uses as much as digits as its factorization.

18202689341801 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1327104, while the sum is 53.

The spelling of 18202689341801 in words is "eighteen trillion, two hundred two billion, six hundred eighty-nine million, three hundred forty-one thousand, eight hundred one".