Base | Representation |
---|---|
bin | 10000111111010001… |
… | …011101110000010001 |
3 | 1202002021102202012001 |
4 | 100333101131300101 |
5 | 244324300141423 |
6 | 12214024434001 |
7 | 1214016305341 |
oct | 207721356021 |
9 | 52067382161 |
10 | 18241412113 |
11 | 781088aa01 |
12 | 3651018901 |
13 | 19492570a2 |
14 | c5090cd21 |
15 | 71b692cad |
hex | 43f45dc11 |
18241412113 has 2 divisors, whose sum is σ = 18241412114. Its totient is φ = 18241412112.
The previous prime is 18241412107. The next prime is 18241412149. The reversal of 18241412113 is 31121414281.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18216091089 + 25321024 = 134967^2 + 5032^2 .
It is an emirp because it is prime and its reverse (31121414281) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 18241412113 - 25 = 18241412081 is a prime.
It is not a weakly prime, because it can be changed into another prime (18241412153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9120706056 + 9120706057.
It is an arithmetic number, because the mean of its divisors is an integer number (9120706057).
Almost surely, 218241412113 is an apocalyptic number.
It is an amenable number.
18241412113 is a deficient number, since it is larger than the sum of its proper divisors (1).
18241412113 is an equidigital number, since it uses as much as digits as its factorization.
18241412113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1536, while the sum is 28.
Adding to 18241412113 its reverse (31121414281), we get a palindrome (49362826394).
The spelling of 18241412113 in words is "eighteen billion, two hundred forty-one million, four hundred twelve thousand, one hundred thirteen".
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