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31121414281 is a prime number
BaseRepresentation
bin11100111110111110…
…110001100010001001
32222022220102122120101
4130332332301202021
51002214040224111
622144051525401
72151134441146
oct347676614211
988286378511
1031121414281
11122202551a1
1260465b9861
132c1c802b49
14171335d3cd
15c222debc1
hex73efb1889

31121414281 has 2 divisors, whose sum is σ = 31121414282. Its totient is φ = 31121414280.

The previous prime is 31121414267. The next prime is 31121414329. The reversal of 31121414281 is 18241412113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19082935881 + 12038478400 = 138141^2 + 109720^2 .

It is an emirp because it is prime and its reverse (18241412113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31121414281 - 225 = 31087859849 is a prime.

It is a super-2 number, since 2×311214142812 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31121414201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560707140 + 15560707141.

It is an arithmetic number, because the mean of its divisors is an integer number (15560707141).

Almost surely, 231121414281 is an apocalyptic number.

It is an amenable number.

31121414281 is a deficient number, since it is larger than the sum of its proper divisors (1).

31121414281 is an equidigital number, since it uses as much as digits as its factorization.

31121414281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1536, while the sum is 28.

Adding to 31121414281 its reverse (18241412113), we get a palindrome (49362826394).

The spelling of 31121414281 in words is "thirty-one billion, one hundred twenty-one million, four hundred fourteen thousand, two hundred eighty-one".