Base | Representation |
---|---|
bin | 10001000101101111… |
… | …101100011111110101 |
3 | 1202100211202120220222 |
4 | 101011233230133311 |
5 | 300040100000432 |
6 | 12232504104125 |
7 | 1216505266421 |
oct | 210557543765 |
9 | 52324676828 |
10 | 18350000117 |
11 | 7867107759 |
12 | 3681465045 |
13 | 19658b6847 |
14 | c610d7b81 |
15 | 725e92112 |
hex | 445bec7f5 |
18350000117 has 2 divisors, whose sum is σ = 18350000118. Its totient is φ = 18350000116.
The previous prime is 18350000099. The next prime is 18350000131. The reversal of 18350000117 is 71100005381.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14224378756 + 4125621361 = 119266^2 + 64231^2 .
It is an emirp because it is prime and its reverse (71100005381) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 18350000117 - 214 = 18349983733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (18350006117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9175000058 + 9175000059.
It is an arithmetic number, because the mean of its divisors is an integer number (9175000059).
Almost surely, 218350000117 is an apocalyptic number.
It is an amenable number.
18350000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
18350000117 is an equidigital number, since it uses as much as digits as its factorization.
18350000117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 840, while the sum is 26.
Adding to 18350000117 its reverse (71100005381), we get a palindrome (89450005498).
The spelling of 18350000117 in words is "eighteen billion, three hundred fifty million, one hundred seventeen", and thus it is an aban number.
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