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18441049641481 is a prime number
BaseRepresentation
bin1000011000101101001000…
…01101101001001000001001
32102021221120110022212121101
410030112210031221020021
54404114232202011411
6103115411245341401
73612215254431565
oct414264415511011
972257513285541
1018441049641481
11596a894846895
122099bba267861
13a39ca2a3b5ac
1447a7a16cc6a5
1521ea624c38c1
hex10c5a4369209

18441049641481 has 2 divisors, whose sum is σ = 18441049641482. Its totient is φ = 18441049641480.

The previous prime is 18441049641457. The next prime is 18441049641517. The reversal of 18441049641481 is 18414694014481.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12633475009600 + 5807574631881 = 3554360^2 + 2409891^2 .

It is a cyclic number.

It is not a de Polignac number, because 18441049641481 - 241 = 16242026385929 is a prime.

It is a super-2 number, since 2×184410496414812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (18441019641481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9220524820740 + 9220524820741.

It is an arithmetic number, because the mean of its divisors is an integer number (9220524820741).

Almost surely, 218441049641481 is an apocalyptic number.

It is an amenable number.

18441049641481 is a deficient number, since it is larger than the sum of its proper divisors (1).

18441049641481 is an equidigital number, since it uses as much as digits as its factorization.

18441049641481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3538944, while the sum is 55.

The spelling of 18441049641481 in words is "eighteen trillion, four hundred forty-one billion, forty-nine million, six hundred forty-one thousand, four hundred eighty-one".