Search a number
-
+
18499499477 is a prime number
BaseRepresentation
bin10001001110101001…
…111111010111010101
31202202021001221111022
4101032221333113111
5300341332440402
612255404250525
71223302102544
oct211651772725
952667057438
1018499499477
117933537848
123703540a45
13198a86b8c4
14c76cd215b
157341732a2
hex44ea7f5d5

18499499477 has 2 divisors, whose sum is σ = 18499499478. Its totient is φ = 18499499476.

The previous prime is 18499499471. The next prime is 18499499507. The reversal of 18499499477 is 77499499481.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9555258001 + 8944241476 = 97751^2 + 94574^2 .

It is a cyclic number.

It is not a de Polignac number, because 18499499477 - 26 = 18499499413 is a prime.

It is a super-3 number, since 3×184994994773 (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 18499499477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (18499499471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9249749738 + 9249749739.

It is an arithmetic number, because the mean of its divisors is an integer number (9249749739).

Almost surely, 218499499477 is an apocalyptic number.

It is an amenable number.

18499499477 is a deficient number, since it is larger than the sum of its proper divisors (1).

18499499477 is an equidigital number, since it uses as much as digits as its factorization.

18499499477 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 164602368, while the sum is 71.

The spelling of 18499499477 in words is "eighteen billion, four hundred ninety-nine million, four hundred ninety-nine thousand, four hundred seventy-seven".