Base | Representation |
---|---|
bin | 1000100001100111011000… |
… | …11000110110011011110111 |
3 | 2110101012210211021221020012 |
4 | 10100303230120312123313 |
5 | 4424123233010422033 |
6 | 103512202443130435 |
7 | 3643304113044122 |
oct | 420635430663367 |
9 | 73335724257205 |
10 | 18747203217143 |
11 | 5a7870a528605 |
12 | 2129400513a1b |
13 | a5cb136b751b |
14 | 48b525bb93b9 |
15 | 2279d0004248 |
hex | 110cec6366f7 |
18747203217143 has 2 divisors, whose sum is σ = 18747203217144. Its totient is φ = 18747203217142.
The previous prime is 18747203217089. The next prime is 18747203217151. The reversal of 18747203217143 is 34171230274781.
It is a strong prime.
It is an emirp because it is prime and its reverse (34171230274781) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-18747203217143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 18747203217091 and 18747203217100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (18747203217163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9373601608571 + 9373601608572.
It is an arithmetic number, because the mean of its divisors is an integer number (9373601608572).
Almost surely, 218747203217143 is an apocalyptic number.
18747203217143 is a deficient number, since it is larger than the sum of its proper divisors (1).
18747203217143 is an equidigital number, since it uses as much as digits as its factorization.
18747203217143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1580544, while the sum is 50.
The spelling of 18747203217143 in words is "eighteen trillion, seven hundred forty-seven billion, two hundred three million, two hundred seventeen thousand, one hundred forty-three".
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